Theorem·T01
Existence of the empty set
There is a set with no members.
This
is the empty set
of D002. Moreover this
is unique, by Extensionality.
In words
There is a set B such that, for every x, x is not a member of B. This B is unique, and it is called the empty set.
Never needed: F03 · F04 · F05 · F06 · F08 · F10 · F11 · F12 · F13 · A02 · A03 · A04 · A07 · A08 (computed from the citation graph, not asserted).
Proof
- 1By Infinity there is a set (the axiom asserts the existence of such an ), so there is at least one set to apply Separation to.
- 2Apply Separation to with the contradictory property , which nothing satisfies. We obtain the set .
- 3For every , , which never holds; hence . So has no members, and is the empty set of D002.
- 4For uniqueness: if is any other set with no members, then and have the same (no) members, so by Extensionality . Hence the empty set is unique.
∎
Remarks
Demoted from an axiom: many textbook presentations of ZFC carry "empty set existence" as a separate axiom, but it is derivable from Separation applied to any set that exists (existence being provided by Infinity). The proof needs only the existence clause of Infinity, not its full strength; its real job is establishing a set to which Separation can be applied.
Propose an edit4 published revisions
- 7/11/2026 · Benjamin· Fix Mathlib link: add the #doc fragment doc-gen4's find endpoint requires (old link 404'd). Content unchanged.what changed →
- 7/11/2026 · Benjamin· Restructure: demote empty set to a theorem T01what changed →
- 7/11/2026 · Benjamin· Backfill: add plain-English prose and Mathlib docs linkwhat changed →
- 7/11/2026 · Benjamin· Initial foundations seedwhat changed →