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Theorem·T22

The integers form an abelian group under addition

Addition of integers is associative and commutative, has an identity, and every integer has an additive inverse.

(D058) is a group, and is commutative: it is abelian.
In words
Adding integers is associative and commutative, has an identity, and every integer has an additive inverse: the integers, with addition, form an abelian group.
Never needed: F05 · F10 · F13 · A03 · A04 · A05 · A07 (computed from the citation graph, not asserted).

Proof

  1. 1
    Closure. For , directly by D058 (the result is again a class ).
  2. 2
    Associativity. Let . Two applications of D058 each give These agree by associativity of addition on in each coordinate.
  3. 3
    Commutativity. With as above, and are equal since and by commutativity of addition on .
  4. 4
    Identity. ( from D057) using D027 in each coordinate; by commutativity (part 3), too.
  5. 5
    Inverses. For , let . By D058, . Since by commutativity, and both and by D027 and commutativity, we get , i.e. (L41). So by T04. By commutativity, too.
  6. 6
    All clauses (G1)-(G3) of D038 hold for , plus commutativity: is an abelian group.

Remarks

This is exactly the repair noted as missing from : the naturals have an identity but no inverses, and the integers were built precisely to fix that. Uniqueness of the identity and of inverses now follows for free from L28; the inverse of is written , constructed explicitly in D059.

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