Lemma·L29
The coset equivalence relation
Sharing a coset is an equivalence, and the classes are the cosets.
Let
be a subgroup and define the relation
on
by
Then (i)
is an equivalence relation on
, and (ii) its classes are the left cosets:
for every
.
In words
For a subgroup H of a group G, call two group elements a and b related exactly when the inverse of a times b lands in the subgroup. This relation is reflexive, symmetric and transitive, and the equivalence class is exactly the left coset, for every element a.
Never needed: F03 · F04 · F06 · F08 · F10 · F11 · F12 · A03 · A04 · A05 · A07 · A08 (computed from the citation graph, not asserted).
Proof
- 1is a set of pairs by Separation inside , hence a relation on (D012, D011).
- 2
- 3
- 4
- 5(ii), classes are cosets: fix . If , i.e. (D021), then by (G1), (G2, G3) and D040. Conversely if , say with , then so . Extensionality gives .
∎
Remarks
Congruence modulo a subgroup: for the additive group of integers and the subgroup of multiples of
, this relation is precisely congruence mod
. Feeding (i) into T04 shows the left cosets partition
; with the uniform size from L30, the partition counts itself into Lagrange's theorem.